RBSE Class 12 Maths Solutions Chapter 5 Continuity and Differentiability Ex 5.6

Topprs
0

RBSE Class 12 Maths Solutions Chapter 5 Continuity and Differentiability Ex 5.6

Question 1.

x = 2at2, y = at4
Answer:
Given x = 2at2, y = at4
Differentiating both sides w.r.t t

Question 2.
x = a cos θ, y = b cos θ
Answer:
Given, x = a cos θ, y = b cos θ
Differentiating both sides w.r.t θ

Question 3.
x = sin t, y = cos 2t
Answer:
Given x = sin t and y = cos 2t
Differentiating both sides w.r.t t

Question 4.
x = 4t and y = 4t
Answer:
Given, x = 4t and y = 4t
Differentiating both sides w.r.t t

Question 5.
x = cos θ - cos 2θ, y = sin θ - sin 2θ
Answer:
Given, x = cos θ - cos 2θ
and y = sin θ - sin 2θ
Differentiating both sides w.r.t. θ

Question 6.
x = a(θ - sin θ), y = a(1 + cos θ)
Answer:
Given x = a(θ - sin θ)
and y = y = a(1 + cos θ)
Differentiating both sides w.r.t. θ

Question 7.
x = sin3tcos2t, y = cos3tcos2t
Answer:


RBSE Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.6 9

Question 8.
x = a(cos t + log tan t/2), y = a sin t
Answer:
x = a(cos t + log tan t/2), y = a sin t
Differentiating both sides of t
x = a(cos t + log tan t/2)

Question 9.
x = a sec θ, y = b tan θ
Answer:
Given, x = a sec θ, y = b tan θ
Differentiating both sides w.r.t. θ

Question 10.
x = a(cos θ + θ sin θ)
y = a(sin θ - θ cos θ)
Answer:
Given, x = a(cos θ + θ sin θ)
and y a(sin θ - θ cos θ)
Differentiating both functions w.r.t. θ

Question 11.
If x = asin1t and y = acos1t, then show that dydx=yx.
Answer:

सभी प्रकार के नोट्स TOPPRS.IN पर FREE उपलब्ध है !

Post a Comment

0Comments

Either way the teacher or student will get the solution to the problem within 24 hours.

Post a Comment (0)
close